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A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is insulated with 3 cm thick asbestos (k = 0.2 W/mK). If the temperature difference between the innermost and outermost surfaces is 600 deg * C the heat transfer rate per unit length is: (a) 0.94W / m (b) 9.44W / m (c) 944.72W / m (d) 9447.21W / m 135?
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A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is...
Given Data:
- Inner diameter (ID) = 2 cm
- Outer diameter (OD) = 5 cm
- Thickness of asbestos insulation = 3 cm
- Thermal conductivity of stainless steel (ks) = 19 W/m*K
- Thermal conductivity of asbestos (k) = 0.2 W/m*K
- Temperature difference = 600°C

Calculations:
1. Calculate the outer radius of the stainless steel tube:
- Outer radius (Ro) = OD/2 = 5 cm / 2 = 2.5 cm = 0.025 m
2. Calculate the inner radius of the stainless steel tube:
- Inner radius (Ri) = ID/2 = 2 cm / 2 = 1 cm = 0.01 m
3. Calculate the area of heat transfer:
- A = 2πL * (Ro + Ri) = 2πL * (0.025 + 0.01) = 2πL * 0.035
4. Calculate the thermal resistance of stainless steel:
- Rss = ln(Ro/Ri) / (2πL*ks) = ln(0.025/0.01) / (2πL*19) = 0.6923 / (38πL)
5. Calculate the thermal resistance of asbestos:
- Ra = ln(Ro/Ri) / (2πL*k) = ln(0.025/0.01) / (2πL*0.2) = 0.6923 / (0.4πL)
6. Calculate the total thermal resistance:
- Rtotal = Rss + Ra = 0.6923 / (38πL) + 0.6923 / (0.4πL)
7. Calculate the heat transfer rate per unit length:
- Q = ΔT / Rtotal = 600 / (0.6923 / (38πL) + 0.6923 / (0.4πL))

Final Answer:
The heat transfer rate per unit length is approximately 9.44 W/m. Therefore, the correct option is (b) 9.44 W/m.
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A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is insulated with 3 cm thick asbestos (k = 0.2 W/mK). If the temperature difference between the innermost and outermost surfaces is 600 deg * C the heat transfer rate per unit length is: (a) 0.94W / m (b) 9.44W / m (c) 944.72W / m (d) 9447.21W / m 135?
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A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is insulated with 3 cm thick asbestos (k = 0.2 W/mK). If the temperature difference between the innermost and outermost surfaces is 600 deg * C the heat transfer rate per unit length is: (a) 0.94W / m (b) 9.44W / m (c) 944.72W / m (d) 9447.21W / m 135? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is insulated with 3 cm thick asbestos (k = 0.2 W/mK). If the temperature difference between the innermost and outermost surfaces is 600 deg * C the heat transfer rate per unit length is: (a) 0.94W / m (b) 9.44W / m (c) 944.72W / m (d) 9447.21W / m 135? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stainless steel tube (k_{s} = 19W / m * K) of 2 cm ID and 5 cm OD is insulated with 3 cm thick asbestos (k = 0.2 W/mK). If the temperature difference between the innermost and outermost surfaces is 600 deg * C the heat transfer rate per unit length is: (a) 0.94W / m (b) 9.44W / m (c) 944.72W / m (d) 9447.21W / m 135?.
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